[python] Zope: ako uploadovat subory cez Controller Page Template?

[Martin Stofcik]

V zope v Controll Page Template form.cpt mam nieco ako:

<form enctype="multipart/form-data">
<input type="file" name="file"/>
<input class="button continue"
       type="submit"
       name="form.button.Save"
       value="Ulozit"/>
<input type="hidden" name="form.submitted" value="1" />
</form>

spracovanim tohto formulara sa dostanem cez premennu file iba k nazvu
suboru. Ako by som vedel dostat cely subor z tohto formulara? Napriklad
tak ako to je v Page Template.

Napr. ak formular bude vyzerat takto:

<form enctype="multipart/form-data" action="skript">
<input type="file" name="file"/>
<input class="button continue"
       type="submit"
       name="form.button.Save"
       value="Ulozit"/>
<input type="hidden" name="form.submitted" value="1" />
</form>

a ak dam v sktripe zobrazit context.REQUEST tak ten mi zobrazi nieco
ako:

form

file <ZPublisher.HTTPRequest.FileUpload instance at 0x451e94cc>
...

tak toto by som chcel docielit aj pri Controll Page Template, viete ako
na to?

--
Martin Stofcik